如果想要做一个比较漂亮的Applet让人家使用一定会加上很多资源比如图片或者声音文件什么的 sun提供了一个有用的工具jar这个工具可以把这些资源文件合在一个文件里避免频繁的http request 而且下载的jar文件可以被缓存很爽吧 但是如何正确引用jar中的资源呢? 比如我们打算显示一个图片按钮图片相对路径为/img/logogif你可以自己随便找一个gif图片 让我们来看看我们想当然的做法 import javaawt*; import javaawtevent*; import javaxswing*; public class ImageButtonApplet extends JApplet { private String path = /img/logogif; private ImageIcon logoButtonIcon = new ImageIcon(path); /**Initialize the applet*/ public void init() { try { if (logoButtonIcon == null) throw new Exception(cannot get the image!); JButton iButton = new JButton(logoButtonIcon); Container cp = thisgetContentPane(); cpadd(iButton); } catch (Exception e) { eprintStackTrace(); } } } 这样子编译之后把ImageButtonAppletclass和logogif保持相对路径打进jar里面对应的HTML页面代码为由于使用了Swing 经过HTMLConverter预处理之后本以为能够一举成功打开页面却发现抛出异常 javasecurityAccessControlException: access denied (javaioFilePermission /img/logogif read) 这件事情也郁闷了我很久反复试验不管path相对路径还是什么都不能顺利实现 后来我研究了jdk自带的demo发现demo在引用资源的时候采用这样的方法 getClass()getResource(String sourceName); getClass()是Object的方法返回一个对象的运行时类型即CLass对象 原来Class对象有getResource方法在API文档中就是这样写的 public URL getResource(String name) Finds a resource with a given name This method returns null if no resource with this name is found The rules for searching resources associated with a given class are implemented by the * defining class loader of the class This method delegates the call to its class loader after making these changes to the resource name: if the resource name starts with / it is unchanged; otherwise the package name is prepended to the resource name after converting to / If this object was loaded by the bootstrap loader the call is delegated to ClassLoadergetSystemResource Parameters: name name of the desired resource Returns: a URL object Since: JDK See Also: ClassLoader 如法炮制我把原来的 private ImageIcon logoButtonIcon = new ImageIcon(path); 改成 private ImageIcon logoButtonIcon = new ImageIcon(getClass()getResource(path)); 编译jarrun成功无论是本机打开还是放到http服务器中都没有问题了 这就是在Applet中引用jar中资源文件的KEY! |